9s^2+24s+16=49

Solution for 9s^2+24s+16=49 equation:

9s^2+24s+16=49

We move all terms to the left:

9s^2+24s+16-(49)=0

We add all the numbers together, and all the variables

9s^2+24s-33=0

a = 9; b = 24; c = -33;
Δ = b2-4ac
Δ = 242-4·9·(-33)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-42}{2*9}=\frac{-66}{18}
=-3+2/3
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+42}{2*9}=\frac{18}{18}
=1
$